what is likely to be the quantum number for a circular orbit of diameter 20nm of the hydrogen atom if we assume bohr orbit to be same as that represented by the principal quantum number?

Bohr radius is given as,
rn = 0.529 n2×10-10 m
given that, diameter = 20 nm
Therefore, radius = 10nm =  10×10-9 m
Using Bohr radius equation:
n2 = 10×10-90.529×10-10 = 189.03n = 13.74  14
 

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