# what is liquid junctionpoint and liquid junction potential plzexplain with figure if possible.

This liquid junction potential can be calculated as follows,

In the case of two solutions of different concentrations of HCl,

Electromotive force(EMF) without transference,

E

_{1}= RT/F x ln(a

_{2}/a

_{1})

where a

_{2}and a

_{1}being the activities of HCl in the two solutions, R being the universal gas constant, T being the temperature and F being the Faraday's constant

EMF with transference,

E

_{2}= t

_{M}RT/F x ln(a

_{2}/a

_{1})

where t

_{M}being transport number of Cl

^{-}

Liquid junction potential = E

_{2}- E

_{1}

_{ }= (t

_{M}- 1) RT/F x ln a

_{2}/a

_{1}

_{.}

**
**