What is sulphuric acid reducing to what?
Q.(e). Reducing property of sulphuric acid is used.
$\underset{(Conc.)}{H_{2}S{O}_4}+H_{2}S \left(g\right)\to 2H_{2}O \left(l\right)+2S \left(s\right)+S{O}_2 \left(g\right)$

The solution is as follows:

1. Sulphuric acid is reduced to form Sulphur dioxide and Hydrogen sulphide is oxidised to form sulphur element.

2. This is as shown below:

          H₂SO₄(conc) + H₂S(g) $\to$ 2 H₂O (l) + 2S (s) + SO₂(g)

             +6                     -2                                 0           +4

Thus, sulphuric acid is oxidising in nature.