what is the amount of heat required to convert 10 gram of ice at zero degree celsius to steam at hundred degree Celsius

Solution:

In this question you just have know the step how ice is converting

steps

  1.  0 ice to 0 water.this is the process of phase change temperature remain constant in this process but heat is taken.
  2. convert 0 water to 100 water
  3. 100 water to 100. steam this is the process of phase change temperature remain constant in this process but heat is taken.

so total heat required = heat taken to convert 0ice to 0 water +heat taken to convert 0 water to 100 water +heat taken to convert 100 water to 100 steam Total heat absorbed

ΔHfusion+ΔHtemp.rise+ΔHvap.heat of fusion=80cal/gΔHfusion= mL =10×80 =800 calSpecific heat capacity for water c =1ΔT=change in temperature=100ΔHtemp.rise=mcT =10×1×100 =1000 calheat of vaporization =540cal/gΔHvap.=10×540 =5400 cal So ΔHfusion+ΔHtemp.rise+ΔHvap.=7200cal


 

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