What is the answer for question 21 and it’s explanation
Dear Student
Option (c) is the answer.
(a) represents at t = 0, particle is at zero and slope decreases , becomes 0 and then negative.
At t = 0, particle has positive velocity.
(b) Let us take particle at particle zero, the particle would either have positive or negative velocity but not zero.
(c) At t = 0, slope of DT graph is zero, the slope initially increases then decreases.
At t = 0 particle is at rest, speed = 0, so velocity = zero.
(d) At t = 0, particle has positive velocity that decreases.
Regards
Option (c) is the answer.
(a) represents at t = 0, particle is at zero and slope decreases , becomes 0 and then negative.
At t = 0, particle has positive velocity.
(b) Let us take particle at particle zero, the particle would either have positive or negative velocity but not zero.
(c) At t = 0, slope of DT graph is zero, the slope initially increases then decreases.
At t = 0 particle is at rest, speed = 0, so velocity = zero.
(d) At t = 0, particle has positive velocity that decreases.
Regards