What is the answer Share with your friends Share 5 Shrutina Agarwal answered this Dear Student, Given BE = DFSo, In triangle OFDOF2 + FD2 = OD2 (By Pythagoras theorem)OF2 = OD2 - FD2OF = OD2 - DF2And, In triangle OFCOF2 + FC2 = OC2 (By Pythagoras theorem)Since, OC = OD (radius of the circle)So, OF2 + FD2 = OF2 + FC2 FD2 = FC2 FD = FCSo, CD = DF + FC = DF + DF = 2DFSimilarly,AB = 2BEIn triangle OEBOE2 + BE2 = OB2 (By Pythagoras theorem)OE2 = OB2 - BE2OE = OB2 - BE2So, ABCD×OFOE= 2BE2DF×OD2 - DF2OB2 - BE2Since, BE = DF (given) and OD = OB (radius of the circle)ABCD×OFOE= 2BE2DF×OD2 - DF2OB2 - BE2 = 1 Regards, 2 View Full Answer Viraj answered this ans is a 1 1 Smitha Meti answered this Thanks.....but plzzz explain it 2 Manish 💞 ❤️branded answered this Hlw dear -1 Manish 💞 ❤️branded answered this May I help u -3 Manish 💞 ❤️branded answered this It's very easy question -1 Sahil Sharma answered this The answer is 1. 2 Smitha Meti answered this Ok tell me..... 1 Manish 💞 ❤️branded answered this Ok wait 1 Manish 💞 ❤️branded answered this Kahi jana mat -2 Smitha Meti answered this Tik hai.... -1 Manish 💞 ❤️branded answered this Hope it's helpful 8 Manish 💞 ❤️branded answered this Please find this answer -3 Manish 💞 ❤️branded answered this Hlw dear smitha see my answers 2 Manish 💞 ❤️branded answered this R u there dear.....???? 1 Smitha Meti answered this Ya i am here 1 Smitha Meti answered this And also thank you very much.... 1