What is the answer

Dear Student,
Given BE = DFSo, In triangle OFDOF2 + FD2 = OD2       (By Pythagoras theorem)OF2  = OD2 -  FD2OF = OD2 -  DF2And,  In triangle OFCOF2 + FC2 = OC2                   (By Pythagoras theorem)Since, OC = OD (radius of the circle)So, OF2 + FD2  = OF2 + FC2  FD2  =  FC2 FD = FCSo, CD = DF +FC = DF +DF = 2DFSimilarly,AB = 2BEIn triangle OEBOE2 + BE2 = OB2       (By Pythagoras theorem)OE2 = OB2 - BE2OE = OB2 - BE2So, ABCD×OFOE=  2BE2DF×OD2 -  DF2OB2 - BE2Since, BE = DF (given)  and OD = OB (radius of the circle)ABCD×OFOE=  2BE2DF×OD2 -  DF2OB2 - BE2 = 1

Regards,

  • 2
ans is a 1
 
  • 1
Thanks.....but plzzz explain it
  • 2
Hlw dear
  • -1
May I help u
  • -3
It's very easy question
  • -1
The answer is 1.
  • 2
Ok tell me.....
  • 1
Ok wait
  • 1
Kahi jana mat
  • -2
Tik hai....
  • -1
Hope it's helpful

  • 8
Please find this answer

  • -3
Hlw dear smitha see my answers
  • 2
R u there dear.....????
  • 1
Ya i am here
  • 1
And also thank you very much....
  • 1
What are you looking for?