# What is the area of triangle with base4.8cm and height3.0cm?

$Areaoftriangle=\frac{1}{2}\times base\times height\phantom{\rule{0ex}{0ex}}Areaoftriangle=\frac{1}{2}\times 4.8\times 3\phantom{\rule{0ex}{0ex}}Areaoftriangle=2.4\times 3\phantom{\rule{0ex}{0ex}}Areaoftriangle=7.2c{m}^{2}\phantom{\rule{0ex}{0ex}}$

Regards

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