What is the bond order of N2+?

There are 14 electrons in N2 molecule, therefore we have the following arrangement of electrons

(σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (Π2px 2 = Π2py 2)(σ2p z )2

here bond order is = (Nb-Na) / 2 = (10-4) / 2 = 3

Now because in N2+, there is one electron less in bonding orbital as compared to electrons in N2, therefore, there will be 1 electron less in the σ2p z orbital.  Therefore we have the following arrangement of electrons

(σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (Π2px 2 = Π2py 2)(σ2p z )1

Thus the bond order in N2+ ion will be

= (9-4) / 2 = 2.5

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