what is the dimension of resistance....????

[R] = ML2T-1C-2

yo!

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Dimension of resistance can be worked out by using Ohm's law

You know V = IR or R = V/I....(1)

The dimensional formalism of equation (1) can be written as follows

[R] = [V]/[I] = [W/q]/[I]  { since potential refers to work done(W) per unit charge }

So [R] = [w]/[qI] = [W]/[I2T]   { [I] = [q]/[T] where T stands for time }

thus [R] = [ML2T-2]/[A2T]  {  dimension of current is taken as [A] }

= [M1L2T1A-2]  (ans)

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thnkx....

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thnkx dude....

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thank you!!

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• [M][L]2 [T]-3 [I]-2
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Ml2
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Here

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can a body have a charge of 1.8x10-19C?

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