what is the formula for a3+b3+c3?
We know that ,
a3+b3+c3 - 3abc = (a+b+c)*(a2+b2+c2-ab-bc-ac)
So a3+b3+c3 =(a+b+c)*(a2+b2+c2-ab-bc-ac)+3abc
a3+b3+c3 - 3abc = (a+b+c)*(a2+b2+c2-ab-bc-ac)
So a3+b3+c3 =(a+b+c)*(a2+b2+c2-ab-bc-ac)+3abc