What is the magnitude of electric field intensity due to a dipole of moment 2 x 10*8 Cm at a - Physics - Electrostatic Potential And Capacitance

Question

​What is the magnitude of electric field intensity due to a
dipole of moment 2 x 10*8 Cm at a point distant 1 m from the centre
of dipole,when line joining the point to the centre of dipole makes
an angle 60 degree with dipole axis?

Vikas · Accepted Answer

Electric field intensity due to a dipole moment is given as which makes an an angle of 60 degree with dipole axis isE =14πεpcosθr^2following values are given in question dipole moment (p) =2×10^8distance  r =1m   ,and  θ = 60 degreenow put all the values in the above formula ,we getE = 14πε2×10^8 cos 601^2 = 9×10^9 ×10^8                          ,because we know cos 60 = 12 ,and 14πε =9×10^9 E = 9×10^17 ans

​What is the magnitude of electric field intensity due to a dipole of moment 2 x 10*8 Cm at a point distant 1 m from the centre of dipole,when line joining the point to the centre of dipole makes an angle 60 degree with dipole axis?

What is the magnitude of electric field intensity due to a dipole of moment 2 x 10*8 Cm at a point distant 1 m from the centre of dipole,when line joining the point to the centre of dipole makes an angle 60 degree with dipole axis?