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What is the minimum resistance that could be made with five resistors of value ⅓

Dear Student,
Minimum resistance that could be obtained from all five resistors of resistance R = 1/2 ohms will be by their parallel combination.
1Req=1R+1R+1R+1R+1R1Req=113+113+113+113+1131Req=3+3+3+3+3=15Req=115 ohms 

Regards

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Put them all in parallel- 

(1/R) = (1/(1/5)) + (1/(1/5)) + (1/(1/5)) + (1/(1/5)) + (1/(1/5)) 

= 5 + 5 + 5 + 5 + 5 = 25 

R = 1/25 ohms 
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bro i think in place of 1/3 it will be 1/5... i have showed the solution of 1/5 above...
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By , Put them all in parallel-?

(1/R) = (1/(1/5)) + (1/(1/5)) + (1/(1/5)) + (1/(1/5)) + (1/(1/5))?

= 5 + 5 + 5 + 5 + 5 = 25?

R = 1/25 ohms therefore resistance is lowest
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By , Put them all in parallel-

(1/R) = (1/(1/5)) + (1/(1/5)) + (1/(1/5)) + (1/(1/5)) + (1/(1/5))

= 5 + 5 + 5 + 5 + 5 = 25

R = 1/25 ohms therefore resistance is lowest
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