what is the normality of a solution of ammonia, whose density is 0.885. it has 23% ammonia by weight -
1) 1.35 2)12.0 3) 19.1 4) 26.0
ans- 12.0 pls ans urgently
To find :
Normality of solution i.e water + ammonia form NH4OH solution = ?
Formula used :
Density of NH4OH = M/V
Given :
Volume = 1L
Density= 0.885
Mass of NH4OH = 1 x 0.885 = 0.885 g
Amount of NH3 = [(23/100) x0.885] = 20.335/100 = 0.20
Normality normality of a solution of ammonia = [(Amount of NH3 in NH4OH/Equivalent Molar mass of NH3) x volume]
=> (0.20/17)x1000 =200/17 = 11.7 = 12 N
Normality of solution i.e water + ammonia form NH4OH solution = ?
Formula used :
Density of NH4OH = M/V
Given :
Volume = 1L
Density= 0.885
Mass of NH4OH = 1 x 0.885 = 0.885 g
Amount of NH3 = [(23/100) x0.885] = 20.335/100 = 0.20
Normality normality of a solution of ammonia = [(Amount of NH3 in NH4OH/Equivalent Molar mass of NH3) x volume]
=> (0.20/17)x1000 =200/17 = 11.7 = 12 N