# What is the probability of the sum of two odd numbers to be even

We know : Probability P ( E ) = $\frac{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{desired}\mathrm{events}\mathrm{n}(\mathrm{E})}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{events}\mathrm{n}(\mathrm{S})}$

But we know sum of any two odd number is always an even number , So

Total desired events n ( E ) = total number of events n ( S )

Therefore,

**Probability of the sum of two odd numbers to be even = 1 ( Ans )**

Hope this information will clear your doubts about topic.

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