What is the Probability that an ordinary year has 53 Sundays?

The number of days in an ordinary year = 365

The number of days in a week = 7

∴ Number of complete weeks in a year = 365 ÷ 7

On dividing 365 by 7, we obtain that there are 52 complete weeks in a year and 1 day is left as remainder.

Every week has 1 Sunday, so there must be 52 Sundays in a year.

Now, the remaining 1 day can be any one of the 7 days.

Hence, the probability for the remaining day of being Sunday = 

 

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1/7
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1/7 it is prfectly right
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1/7
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1/7 
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