what is the ratio of solubilities of N2 and O2 in H2O at 373K given that KH(N2) = 12 - Chemistry - Solutions

Question

what is the ratio of solubilities of N2 and
O2 in H2O at 373K? given that
KH(N2) = 12 6 X 104 atm and
KH(O2) = 7 01 X 104 atm assume
that P(N2) = 0 8 atm and P(O2) = 0 2 atm

Urvashi Yadav · Accepted Answer

Given:

KH(N2)
= 12 6 X 104
atm

KH(O2)
= 7 01 X 104

atm

P(N2)
= 0 8 atm

P(O2)
= 0 2 atm
Partial pressure of the gas is proportional to mole fraction of
the gas in the solution
X(N2) = p(N2) / kH(N2)
X(O2) = p(O2) / kH (O2)
So ratio of solubilities of N2 and O2:
X(N2) / X(O2) = 0 8 x 7 01 x
104 / 12 6x104 x 0 2
X(N2) / X(O2) = 2 22

what is the ratio of solubilities of N2 and O2 in H2O at 373K? given that KH(N2) = 12.6 X 104 atm and KH(O2) = 7.01 X 104 atm. assume that P(N2) = 0.8 atm and P(O2) = 0.2 atm.

what is the ratio of solubilities of N₂ and O₂ in H₂O at 373K? given that K_H(N₂) = 12.6 X 10⁴atm and K_H(O₂) = 7.01 X 10⁴ atm. assume that P(N₂) = 0.8 atm and P(O₂) = 0.2 atm.