# what is the smallest number with which 12348 must be multiplied to make it a perfect cube* 1*3*2*6Explain why????????? i did not understand howMy exams are tommorrow pleasee before nihght

First you got to prime factorize the numbers.In this case the numbers are

12348=2 X 2 X 3 X 3 X 7 X 7 X 7

Then we got to group the like numbers in groups of 3s(only for cubes)

so..

Here, the prime factor 7 appears in a group of three whereas the prime factors 2 and 3 do not appear in a group of three (each of them appears twice).

For a number to be a perfect cube, each of its prime factors should occur in groups of three. Thus, we have to make the prime factors 2 and 3 occur in groups of three. For this, we are required to multiply the number by 2 X 3 = 6.

so the smallest number to be multiplied to 12348 is 6.

• 2

First you got to prime factorize the numbers.In this case the numbers are

12348=2 X 2 X 3 X 3 X 7 X 7 X 7

Then we got to group the like numbers in groups of 3s(only for cubes)

so..

Here, the prime factor 7 appears in a group of three whereas the prime factors 2 and 3 do not appear in a group of three (each of them appears twice).

For a number to be a perfect cube, each of its prime factors should occur in groups of three. Thus, we have to make the prime factors 2 and 3 occur in groups of three. For this, we are required to multiply the number by 2 X 3 = 6.

so the smallest number to be multiplied to 12348 is 6.

• 0

first do prime factorization

ur answer wud b :2*2*3*3*7*7*7

here ,7 r in the pair of hree bt 2 n 3 r not.

so both the sides wil b multiplyed by 2*3=6

12348*6=7(taken as single)*6

=74088is the cube of 42.

here it has been multiplyied by 6 bcz v have one 2 n 3 both missin.so they hv 2 be multiplyied n so 2*3=6 will b obtained. hope it heps

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