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what is the sum of natural numbers 1 to 100

sum of first 'n' natural numbers= n(n+1)/2

sum of natural numbers from 1 to 100= 100(100+1)/2

=100(101)/2 = 5050

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also n/2(a+l)

a=first number

l=last number

n=total numbers

100/2(100+1)=5050

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sum=n/2*(a1+an)

n=total terms

a1=1st term

an=last term

s100=100/2*(1+100)=5050

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5050
 
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Sum of first natural numbers(n)= N(n+1)/2
sum of 'n' numbers from 1-100 = 100(100+1)/2
 .     = 100(101)/2 
. .      => 5050
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I got this answer

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Please find this answer

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100?101?2
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5050
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The Equation for the Sum of First 100 Natural Number is
n(n+1)?2
ie.,

100(101)? 2
100?101?2
=5050
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100?101?2=5050
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