what is the total no of candidates at an examination if 31% fail and the number of those who pass exceeds the number of those who fail by 247.?

Solution:

Let us assume that the total number of candidates be X.

Then the total no. ofcandidatesfailed will be 31% of X = 32X/100, then the total no. ofcandidatespassed will be (31X/100 + 247).

Then the equation we get:

31X/100 + (31X/100 + 247) = X

31X/100 + 31X/100 + 247 = X

31X + 31X + 24700 / 100 = X

62X + 24700 = 100X

62X - 100X = -24700

- 38X = -24700

X = 24700/38 = 650 Nos.

Ans: The total no. ofcandidates= 650.

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