What is the total volume of atom present in body centred unit cell having length of one edge as 69.3pm ?

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Dear student
Please find the solution to the asked query:

Total number of atoms in BCC =2
Edge length = 69.3pm​

$$\begin{gathered} For BCC the relation between r (radius ) of the sphere and edge length \left(a\right) \\ is: r=\frac{\sqrt{3}}{4}a \\ Total volume of two atoms \\ = 2\times \frac{4}{3}{\mathrm{\pi r}}^3 \\ =2\times \frac{4}{3}\mathrm{\pi }{\left(\frac{\sqrt{3}}{4}\mathrm{a}\right)}^3 \\ =2\times \frac{4\times 3.14}{3}{\left(\frac{\sqrt{3}}{4}\times 69.3\right)}^3 \\ =226080 \\ =2.26080\times {10}^5 {\mathrm{pm}}^3 \end{gathered}$$

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