What is the value of 2 log 3⁵ - 5 log 3²

A.0
B.3
C.5
D.2

Sol:

2^log ₃ 5  = 2^{log₂ 5 log₃2}
             = (2^log₂5​ ) log₃2 
2^log ₃ 5 ​ = 5 ^log₃2 ​

Therefore,  2^log ₃ 5 - 5 ^log₃2 = 0

Hence Option A) 0 is the correct answer.