What is the value of "a" if the points (3,5) and (7,1) are equidistant from the point (a,0) ?
Given, P(a, 0) is equidistant from A(3, 5) and B(7, 1).
∴ AP = PB
⇒ AP2 = PB2
⇒ (5 – 0)2 + (a – 3)2 = (1 – 0)2 + (7 – a)2 [ Using Distance formula]
⇒ 25 + a 2 – 6a + 9 = 1 + 49 + a2 – 14a
⇒ –16 = –8a
⇒ a = 2
Thus, the value of a is 2.