WHAT IS THE  VALUE OF FORCE OF 100 N IN A SYSTEM HAVING METRE , KILOGRAM AND MINUTE AS FUNDAMENTAL UNITS.

DIMENSION OF FORCE = [M L T^-2]
LET 
M₁,L₁ & T₁ DENOTE  kg, m , sec
M₂,L₂,T₂ DENOTE kg,m ,min
NUMERIC VALUE OF THESE SYSTEMS ARE n₁ AND n₂ RESPECTIVELY
THEN , 
n₁(M₁L₁T₁^-2)=n₂(M₂L₂T₂^-2)
n₂=n₁ (M₁/M₂) (L₁/L₂) (T₁/T₂)^-2
HERE n₁=100
SO,
n₂= 100 (kg/kg) (m/m) (s/min)^-2
   = 100 (kg/kg) (m/) (s/60 s)^-2
   = 100*60*60
  = 3.6*10⁵
THE FORCE IS 3.6*10⁵ kg m min^-2.