What is the value of the ionisation constantKa of an acid HAif the pH of its 0.01 molar solution is 2? Share with your friends Share 1 Vartika Jain answered this Dear Student, HA ↔ H+ + A-Ka=[H+][A-][HA]pH= 2i.e. -log[H+]=2or, [H+]=10-2 MFrom dissociation equation we know there is a 1:1 molar ratio between [H+] and [A-]Therefore, [A-]=10-2 Mand, [HA]= 0.01 MTherefore, Ka=(10-2)(10-2)(0.01)= 10-2 Hence, the ionisation constant of acid is 10-2 0 View Full Answer
