What is the value of x?
Dear student,
3e- + MnO4- + 2H2O --> MnO2 + 4OH- ] x 8
S2O3 2- + 10OH- ----> 2SO4 2- + 5H2O + 8e- ] x 3
24e- + 8MnO4- +16H2O -----> 8MnO2 + 32OH-
3S2O32- + 3OH- ----> 6SO4 2- + 15H2O + 24e-
Adding all reactants and productants,we get,
8MnO4- + 3S2O32- + H2O ----> 8MnO2 + 6SO4 2- + 2OH-
8 moles of MnO4- ion gives 6 moles of SO42- ion
So.the correct option is (1).
Regards,
3e- + MnO4- + 2H2O --> MnO2 + 4OH- ] x 8
S2O3 2- + 10OH- ----> 2SO4 2- + 5H2O + 8e- ] x 3
24e- + 8MnO4- +16H2O -----> 8MnO2 + 32OH-
3S2O32- + 3OH- ----> 6SO4 2- + 15H2O + 24e-
Adding all reactants and productants,we get,
8MnO4- + 3S2O32- + H2O ----> 8MnO2 + 6SO4 2- + 2OH-
8 moles of MnO4- ion gives 6 moles of SO42- ion
So.the correct option is (1).
Regards,