What is the Van't Hoff Factor in K4[Fe(CN)6] and BaCl2 ? AND How it is calculated here ?
Von’t Hoff factor may be defined as
= 
When K4[Fe(CN)6] dissociate, it gives four K+ ion and one [Fe(CN)6]4- ion therefore Von’t Hoff factor is 5/1 = 5
Similarly for BaCl2, Von’t Hoff factor is 3