What is the work done by an external force in stretching a spring having spring constant k=100 N/m by 10 cm from its unstretched position? Share with your friends Share 0 Saksham Garg answered this Dear Student, Given,K=100N/mx=10cm100cm=1mThen,x=10/100mx=0.1mWs=12K[(xi)2-(xf)2]Ws=12×100[(0)2-(0.1)2]JouleWs=50[0-0.01]JouleWs=50×0.01JouleWs=0.5Joule Regards 0 View Full Answer