What least number must be added to 2whole 1/3 to make sum of a whole number?

Dear Student,

Please find below the solution to the asked query:

We have : $2\frac{1}{3} = \frac{6 + 1}{3} = \frac{\mathbf{7}}{\mathbf{3}}$ , Here we can see that denominator of fraction = 3  and to get sum of this given number and the least number we need to find is in whole number , we can say that our least number could be  = $\frac{x}{3}$

And

$\frac{7}{3}+\frac{x}{3} = \frac{7 + x}{3}$ , Now we put least value of ' x '  as " 7 + x " will be divisible by ' 3 ' and we know number greater than 7 and divisible to 3 is  = 9  , So

7 + x  = 9 ,

x  = 2

Therefore,

Required least number    = $\frac{2}{3}$                                       ( Ans )

Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards