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What mass of ammonia will be produced if 28 g nitrogen reacts with 3 g of Hydrogen?

(A) 34 g (B) 3.4g (C) 17 g (D) 31g

Dear Student,
We are given 28g N2 and 3g H2
The reaction between N2 and H2 to give NH3 is as follows:
       N2       +     3H2       →2NH3  28g28gmol-1     3g2gmol-1   =1mol        =1.5molHere H2 is the limiting reagent.3 mol H2 reacts with 1 mol N21.5 mol H2 must react with 0.5 mol N2. But we have 1 mol N2So N2 is present in excess and H2 is the limiting reagent.So now we can compare H2 and NH3 to find amount of NH3 formedmol of H23=mol of NH321.53=mol of NH32mol of NH3= 1 Hence mass of NH3= 1mol x 17gmol-1=17gRegards
 

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