What mass of lead will weigh as much as 8g of iron when both are immersed in water (RD of - Science - Gravitation

Question

What mass of lead will weigh as much as 8g of iron when both are
immersed in water (RD of lead =11& iron=8)

Govind · Answer

Given: Mass of the sinker = 40 g Density of the sinker (lead) = 11
0 g cm–3 (i) Volume of sinker = Mass / Volume = 40 g/11 0 g
cm–3 = 3 64 cm3 (ii) Loss in weight of sinker when immersed
in water = Weight of water displaced by the sinker = Volume of
sinker × density of water × g = 3 64 × 1 = 3 64
gf (iii) Weight of sinker in water = Weight of sinker in air
– Loss in weight = 40 – 3 64 = 36 36 gf (iv) Weight of
cork in water = Weight of cork together with the sinker in water
– Weight of sinker in water = 11 5 – 36 36 = – 24
86 gf (v) Loss in weight of cork in water = Weight of cork in air
– Weight of cork in water = 6 5 – (– 24 86) = 31
36 gf (vi) R D of cork = (Weight of cork in air) / (Loss in weight
of cork) = 6 5/31 36 = 0 21

What mass of lead will weigh as much as 8g of iron when both are immersed in water (RD of lead =11& iron=8)