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what percent of the lenght of each side of a cube gets decreased when its volume gets decreased by 48.8%?

$L e t o r i g i n a l l e n g t h o f each s i d e o f a c u b e = a S o, o r i g i n a l v o l u m e o f a c u b e = a^{3} N o w, v o l u m e i s d e c r e a s e d b y 48.8 % . S o, n e w v o l u m e o f a c u b e = x^{3} T h e r e f o r e, \frac{a^{3} - x^{3}}{a^{3}} = 48.8 % \Rightarrow \frac{a^{3} - x^{3}}{a^{3}} = \frac{48.8}{100} = 0.488 \Rightarrow a^{3} - x^{3} = 0.488 a^{3} \Rightarrow x^{3} = 0.512 a^{3} \Rightarrow x = 0.8 a N o w, P e r c e n t a g e d e c r e a s e i n l e n g t h = \frac{o l d e r l e n g t h - N e w l e n g t h}{o l d e r l e n g t h} \times 100 % = \frac{a - 0.8 a}{a} \times 100 % = 20 % H e n c e, l e n g t h o f a c u b e i s d e c r e a s e d b y 20 % .$

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