what percentage of kinetic energy of a moving particle is transferred to a stationary particle, when moving particle strikes with a stationary particle of mass 1/19th of its mass? [ans- 99.8%]

Using the relation,
v2f=m2-m1m1+m2v2i+2m1m1+m2v1iAccording to question,v2i=0m1=m (suppose)m2=119mNow,v2f=0+2mm+m19v1i=2m19m+1m19v1i=m10 m19v1iv2f=19 10v1ior v2fv1i=19 10Percentage of energy transferred=1/2 m2v2f21/2 m1v1i2×100=1/191×19×1910×10×100=19100×100=0.19 %

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