What should be the weight of carbon monoxide to have the same number of oxygen atoms as in 22 g of carbon dioxide?

C + O2 CO2

Molar mass of CO2= 44

So, 22 g of CO2 is 0.5 mole.

1 mole of O2 is used to form 1 mole of CO2.

0.5 mole of CO2 will have 0.5 mole of O2= 0.5 * 6.022 * 1023

  = 3.011 * 6.022 * 1023

C + ½ O2 CO

So, 0.5 mole O2 is used to form 1 mole of CO.

1 mole of CO= 28 g.

∴ x/ 28 = 0.5

x= 14 g.

Thus, 14 gm CO will have same number of oxygen atoms as 22 g of CO2.

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 Moles of carbon dioxide = 22/44 = 1/2 = 0.5

Atoms of CO2 = 0.5 * 6.022 * 1023

No. of oxygen atoms = 3.011 * 1023

No. of moles = 3.011 * 1023 / 6.022 * 1023

= 0.5

Molar mass of CO = 28

x /28 = 0.5

x = 14

Ans: 14 g

  • 0

 how did the oxygen atoms came to be 3.011*1023 ,in the above ans. by verma.kirti?

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