What volume of carbon dioxide will be liberated at NTP if 12 g of C burns in excess of O2 (a) 11.2 (b) 22.4 (c) 2,24 (d) 1.12

The balanced reaction is:  C  + O2 = CO2

1 mole of C reacts with q mole of oxygen to form 1 mole of carbon dioxide.

12g of C = 1mole

​So, 1 mole of CO2 will be formed and 1 mole of any gas at NTP has a volume of  24 L (it does not match with any of the options).

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