What will be pOHof solution will be in kolbe'selectrolytic synthesis?

Dear Student,

                      In Kolbe's electrolytic synthesis, aqueous solution of the sodium or potassium salt of Carboxylic acid is electrolysed and alkane is formed at the anode. At cathode , water decomposes to give OH- ions as follows:

At cathode:   2H​2O      +    2e-        --->   2 OH-  + H2

Now from here whatever be the Concentration of OH- ions , take -log10[OH-], thats the pOH of the solution. 

I hope you understood. Keep posting. 




 

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