What will be the de Broglie wavelength of a particle (in angstroms) when it is accelerated by the voltage of 75 volts?
[charge on particle=4e- , mparticle = (1/2) melectron]
Dear Student,
The computation for the wavelength of 75 V is expressed below,
Hence the de Broglie wavelength of a particle is 0.1416 nm.
Regards.
The computation for the wavelength of 75 V is expressed below,
Hence the de Broglie wavelength of a particle is 0.1416 nm.
Regards.