What will be the maximum value of (n + l + m) for all the unpaired electrons of chlorine in its second excited state?

 The maximum value of (n + l + m) for all the unpaired electrons of chlorine in its second excited state.


Electronic configuration of Chlorine atom-
1s² 2s² 2p⁶ 3s² 3p⁵

First exited state Chlorine atom-
1s² 2s² 2p⁶ 3s¹ 3p⁶

Second exited state Chlorine atom-
1s² 2s² 2p⁶ 3s⁰ 3p⁶ 4s¹ 

For only one unpaired electron present in 4s orbital
Value of n = 4
Value of l = 0
Value of m = 0

Therefore, the  maximum value of (n + l + m) for all the unpaired electrons of chlorine in its second excited state
= 4 + 0 + 0
= 4