What will be the ratio of linear momentum, if the masses of two bodies P and Q are in ratio 2 : 3 and their velocities are in ratio 1 : 2 respectively?

Solution,
Given,
masses of two bodies are in the ratio: $m_1:m_2=2:3$
Their velocities are in the ratio: $v_1:v_2=1:2$
Linear momentum is defined as
$p=mv$
Thus,
the ratio of their linear momentum is:
$$\begin{gathered} p_1:p_2=m_1{v}_1:m_2{v}_2 \\ \frac{p_1}{p_2}=\frac{m_1}{m_2}\frac{v_1}{v_2}=\frac{2}{3}\times \frac{1}{2}=\frac{1}{3} \\ Thus, \\ {p}_1:p_2=1:3 \end{gathered}$$