What will be the specific heats of He at constant volume and constant pressure ? Gamma of He = 1.667 , R = 8.318 * 107 erg. mol-1.oC-1 , J = 4.18 * 107 erg.cal-1 and molecular mass of He = 4 . [ Answer : cv = 0.746 cal/g/ oC ; Cp = 1.243 cal/ g/ oC ] Share with your friends Share 0 Krishan Yadav answered this Dear Student, Cp-Cv = R = 8.318 ×107 ---eq1 and CpCv = γ =1..667 = 53⇒Cp = 53CV--------------eq2putting in eq1 53CV-Cv = 8.318 ×10723CV = 8.318 ×107CV =32× 8.318 ×107 = 12.477×107 erg /mol/oC converting to cal/g/oCCV == 12.477×107 4×4.18 ×107 =0.746 cal/g/oCputting this value in eq2 Cp =53*0.746 =1.243 cal/g/oC Regards 0 View Full Answer