What will be the volume of chlorine gas at S.T.P. produced during electrolysis of water molten magnesium chloridewhich produces 6.5 gram of mg

1. The electrolysis reaction is as follows:

       MgCl_​ (l) $\to$ Mg(s) + Cl₂(g)

2. 1 mole MgCl gives 1 mole Mg and 1 mole of Chlorine gas.

         Number of moles of Mg (given) = $\frac{6.5}{24.3}=0.268 moles$

Thus 0.268 moles of Chlorine gas is produced.

3. 1 mole of a gas at STP has Volume 22.4 L
   0.268 mole has volume = 22.4 $\times$ 0.268 = 6.00 L