When 100 ml of M/10 H2SO4is mixed with 500 ml of M/10 NaOHthen resulting solution will be normality - Chemistry - Solutions

Question

When 100 ml of M/10 H2SO4is mixed with 500 ml
of M/10 NaOHthen resulting solution will be & normality of
excess of reactant left is
A)Acidic , N/10
B)Basic , N/5
C)Basic , N/20
D)Acidic ,N/10

HOW SOLVE EXPLAIN ?

Geetha · Accepted Answer

Since the answers are given in Normality, convert molarity into
normality

Normality = Molarity × Basicity (for acid) Normality = Molarity × Acidity (for base)  Given H2SO4 molarity = M10Normality of  H2SO4 =   M10 × 2 (since H2SO4 is dibasic)                                        = 210 = 0
2 NNaOH molarity =M10  Normality of NaOH = M10 × 1 (since NaOH is monobasic)                                    = 110 = 0
1 Nmilli equivalent (meq)= Volume × NormalityFind the meq of acid and base to find the overall solution natureAcid  H2SO4 (volume = 100 ml)                              Base NaOH (volume = 500 ml)100 × 0
2 = 20                                                            500×0
1 = 50Since the base is having more meq, the resulting solution is basic
When these two solutions are mixed, the excess is found with basic solution
i e
, 50 - 20 = 30 meqmeq = Volume × Normality30 = 600 ×Normality (add the two volume for the mixture)Normality = 30600 = 120 N
The resulting solution is basic with 1/20 N Option C is the right
answer

When 100 ml of M/10 H2SO4is mixed with 500 ml of M/10 NaOHthen resulting solution will be & normality of excess of reactant left isA)Acidic , N/10B)Basic , N/5C)Basic , N/20D)Acidic ,N/10 HOW SOLVE EXPLAIN...?

When 100 ml of M/10 H₂SO₄is mixed with 500 ml of M/10 NaOHthen resulting solution will be & normality of excess of reactant left is
A)Acidic , N/10
B)Basic , N/5
C)Basic , N/20
D)Acidic ,N/10

HOW SOLVE EXPLAIN...?