when 123 is added to a perfect square number the new number so formed is also perfect square. find the square root of the new number.

Let the perfect square number be x2 and new perfect sq. number be y2.A/q, y2x2=123=>(y+x)(yx)=41.3y+x=41......(1)and yx=3......(2)Now adding (1) and (2), we get,y=22Putting the value of y in (1),we get x=19.The perfect sq. numbers are 192,i.e.361 and 222,i.e.484.

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