When 4 hydrogen nuclei combine to form a helium nucleus in the interior of the sun, the loss in mass - Physics - Radioactivity

Question

When 4 hydrogen nuclei combine to form a helium nucleus in the
interior of the sun, the loss in mass is 0 0265 amu How much energy
is released

Decoder_2 · Accepted Answer

Dear student,Energy=∆m×c2∆m= loss in mass=0
0265amuc=speed of light=3×108m/secenergy=0
0265×931 5MeV×(3×108)2=0 0265×931 5×1
6×10-13×9×1016Joulesenergy=355
46×103Jenergy=355 46kJRegards

When 4 hydrogen nuclei combine to form a helium nucleus in the interior of the sun, the loss in mass is 0.0265 amu. How much energy is released