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When 9g of solid carbon is burnt in 16g of oxygen gas 22g of carbon dioxide is formed in burning. The mass of carbon dioxide gas formed on burning 3g of carbon in 32g of oxygen is

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Please find the solution to the asked query:

It is given that 9 g of carbon is burnt in 16 g of oxygen 22g of carbon dioxide is produced. How is this? First let us see.

1mol C will react with 1 mol O2
12g C will react with 32g O2
9g C will react with 9/12 x 32  = 24g O2, and 33g CO2 will be produced
Therefore we got to know how 9 g of carbon is burnt in  16g of oxygen 33 g of carbon dioxide is produced there will be no carbon and no oxygen left over.

 
Then they have asked to find mass of carbon dioxide produced on burning 3 g of carbon in 32g of oxygen. 
12g C will react with 32g O2
3g C will react with 3/12 x 32  = 8g O2, and 11g CO2 will be produced.



 
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By the law of definite proportion,the atoms react in the definite proportion to form a compound.Now, Atomic mass of carbon = 12 u and that the molecular mass of oxygen = 32 u.so, In molecule of CO2, 1 carbon atom of mass 12 u combines with a molecule of oxygen of mass 32 u to form CO2.So,their mass ratio of combination in CO2 = 12:32 = 3:8.Now, If 3 g of solid carbon will burn in 32 g of oxygen,then,only 8 g of oxygen will react with 3 g of solid carbon to form CO2.so,total mass of CO2 formed = 3+8 = 11 g.
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