When a 40 V battery is connected across an unknown resistor there is a current of 100 mA in the circuit. Find the value of the resistance of the resister:
(A) 5000 Ω                  (B) 800 Ω                    (C) 0.8 Ω                  (D) none of these

Dear Student ,V = 40V  I = 100 mA = 100 x 10-3  V = IR  R=VI  R=40100x10-3   = .4x102=400ΩSo (d) option is correctRegards

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None of these
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V=40V
I= 100mA = 1/10A or 10^-1A

V=IR
R=V/I =40V / 10^-1A
R=400 ohm
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