when a resistance of 2 ohms is connected across the terminals of a cell the current is 0.5 amperes,when the resistance is increased to 5 ohms, the current is 0.25 amperes. the internal resistance of the cell is Share with your friends Share 32 Vaibhav T. answered this Dear Student, We know thatI=ER+rwhere, I=currentE=emfR=Resistancer=internal resistance0.5=E2+r .................. 1and 0.25=E5+r .....................2from (1) and (2), we get,0.52+r=0.255+r1+0.5r=1.25+0.25r0.25r=0.25r=0.250.25=1 ohm 73 View Full Answer Chandra Mohan C answered this 2.5 -5
