When a silver foil (Z = 47) was used in a alpha ray scattering experiment, the number of particles scattered - Physics - Atoms

Question

When a silver foil (Z = 47) was used in a alpha ray scattering
experiment, the number of particles scattered through
30owas found to be 200 per minute If the silver foil is
replaced by aluminium (Z = 13) foil of same thickness, the number
of alpha particles scattered per minute at 30o is equal
to

Ved Prakash Lakhera · Accepted Answer

Number of alpha particle scattered by silver foil, Ns α  Zse2sinθ24---1and         Nal   α    Zale2sinθ24---2
dividing equation 2 by equation 1, we get,Nal Ns=Zal2Zs2
     or    Nal=  Ns Zal2Zs2
      or     Nal=200×47132
 Nal=200×(3 6154)2=200×13 1o4=2620 8=2621
So approximately 2621 number of alpha particles will be deflected by aluminium foil

When a silver foil (Z = 47) was used in a alpha ray scattering experiment, the number of particles scattered through 30owas found to be 200 per minute. If the silver foil is replaced by aluminium (Z = 13) foil of same thickness, the number of alpha particles scattered per minute at 30o is equal to.