When an electric current is passed through acidulated water 112ml of hydrogen gas at NTP collect at cathode in 965secs. The current passed in ampere is

Dear Student,

The solution to your question is as follows:
22400 mL of hydrogen = 1 mole = 2 gSo, 112 mL of hydrogen contains = 2x11222400=10-2gNow, 2H+ + 2e- H2By Faraday's LawnF=1 molSo, 2 g is deposited by 2x 96500 C0.2 g will be deposited by 2 x 96500 x 10-22=965 CCurrent = Charge time=965 C965 s=1 A

Thus, the current passed is 1 A.

Hope it helps.

Regards
 

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