When the load on a wie is increased slowly from 2kg to 4kg , the elongation increases from 0 6 - Physics - Mechanical Properties Of Solids

Question

When the load on a wie is increased slowly from 2kg to 4kg , the
elongation increases from 0 6 mm to 1 00 mm How much work is done
during the extension of the wire ?

Jyoti Pant · Accepted Answer

Solution: Work done in stretching is: W=1/2x stretching force x extension When stretching force=2 x 9 8N Extension is 0 6mm=0 6x $10^{- 3} m$ Therefore work done W=1/2 x 2 x 9 8x0 6x $10^{- 3}$ =5 88x $10^{- 3}$ J When stretching force is 4 x 9 8N Extension is 1mm=1 x $10^{- 3}$ m Work done W'=1/2x4x9 8x1x $10^{- 3}$ =19 6x $10^{- 3}$ J Now work done in stretching the wire from 0 6mm to 1mm will be W'-W =19 6x $10^{- 3}$ -5 88x $10^{- 3}$ =13 72x $10^{- 3}$ J

When the load on a wie is increased slowly from 2kg to 4kg , the elongation increases from 0.6 mm to 1.00 mm . How much work is done during the extension of the wire ?