when ultraviolet light of wavelength 300nm is incident on a metal plate,a negative potential of 0.54eV is required to stop the emission of photoelectrons .calculate the energy of the incident photon and the workfunction for the metal in eV. Share with your friends Share 10 Ravi Gupta answered this energy of the incident radiationE = hcλ = 6.6×10-34×3×108300×10-9 = 6.6×10-19 joule = 6.6×10-191.6×10-19 =6.6 eVEnergy of the emitted photo electron = 0.54 eVthen work function of metal = 6.6-0.54 = 6.06 eV -11 View Full Answer